In addition to my earlier post. (edit: this post crossed with Hifi_swlon's and Confused's posts) Herman wrote:
And to eleborate a bit on the simple "math".
The basic Ohm's law formula's:
V: Voltage (in V)
R: Resistance (in Ohm)
I: Current (in A)
P: Power (in W)
V = I * R and so I = V/R
P = V * I and so P = V^2 / R
When max. voltage = 40V:
P = 40^2/6=266,67 W
When max. voltage 80V:
P= 80^2/6= 1066,67 W
Quote:The D250 and the D250Pro are both limited by the maximum voltage the Amp can deliver (slightly below 40 Volt per channel - if bridged it can deliver nearly 80 Volt)
=> 40 V are leading to about 266 W in 6 Ohm
=> 80 V are leading to about 1066 W in 6 Ohm
These values are the same for the D200 and the D220PRO but they are artificially limited to about 35 V for the D200 and about 36.5 V for the D220 to take into account their limited heat sinks.
The heat sinks of a D250 is limiting by about 800 W; the D250Pro is now optimized to handle up to 1000 W
And to eleborate a bit on the simple "math".
The basic Ohm's law formula's:
V: Voltage (in V)
R: Resistance (in Ohm)
I: Current (in A)
P: Power (in W)
V = I * R and so I = V/R
P = V * I and so P = V^2 / R
When max. voltage = 40V:
P = 40^2/6=266,67 W
When max. voltage 80V:
P= 80^2/6= 1066,67 W
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