10-Jul-2019, 10:24
There is nothing mysterious.
If you calculate power by squaring the power supply rail voltage and dividing by the load impedance, you're calculating peak power. Amplifier ratings are normally (at any rate, should be) quoted as RMS with a sine wave signal. The peak power for such a signal is exactly twice the RMS power.
Example: 140 Pro PSU rail is 41 V, so peak power into a 6-ohm load is 41^2/6 = 280 W, vs quoted power 140 W RMS.
If you calculate power by squaring the power supply rail voltage and dividing by the load impedance, you're calculating peak power. Amplifier ratings are normally (at any rate, should be) quoted as RMS with a sine wave signal. The peak power for such a signal is exactly twice the RMS power.
Example: 140 Pro PSU rail is 41 V, so peak power into a 6-ohm load is 41^2/6 = 280 W, vs quoted power 140 W RMS.
Roon (Mac Mini), Wilson Benesch Full Circle, Expert 1000 Pro CI, Kaiser Chiara
Warwickshire, UK
